**Drawing Arcs and Constructing Triangles**

To begin with, let's draw the arcs of radius three for a centimeter de as a center cutting DX at F. They also join EF. Since EF is a required triangle, we can proceed by moving how to draw an angle of 90 degrees. Firstly, draw a line that is five centimeters long. Now, draw a semicircle. We can see the arc then drawing EF.

Next, we have to construct angle of 90 degree firstly draw a line be5 centimeter now draw a semicircle we can arc then we draw the angle of 90 degree please here mark another tox now draw a line so it become a 90 degree angle so next step we have to make an arc of three centimeter here it is a three-centimeter give it a name f now join the X and E so it is a right angle triangle. Case number third angle side angle criterion construction of triangle when two of its angles and an included side are given let construct a triangle ABC in which BC is equal to five point six centimeter and angle B 60 degree and angle C 45.

In the previous question, we have given two sides and one angle, in this question, we have given two angles and only one side. So, firstly draw a rough sketch of triangle ABC and mark the given dimensions. Firstly draw a line of five point six centimeter give it a name B and C because we have to find the measure of angle B 60 degree and angle C is equal to 45 degrees so now next step draw a semicircle taking BS enter make an arc now join the line when we measure it with the help of protector we see that it is a 60-degree angle so also we know that we have to find the value of B that means 60 degree.

Moving to the next step, we also find the angle u of angle C 45 degree. Firstly, we have to draw an angle of 90 degree then half of the 90 degree it becomes a 45 so now draw another semicircle taking now C as a centre make an arc from the right and also from the left. Now, make two more arcs please.

Now, take a compass on first arc now please put it on second join the line when we measure measure it with protector it become a 90 degree so how can we find the angle of 45 degree now mark and another arc then we have it and draw a line so it is a angle of 45 degrees in this way we can draw two angles and one side. Join the line five point six centimeter e Y X.

**Construction of Triangle ABC with Given Angles and Side**

Next, let's construct triangle ABC with given angles and side. Let's construct a right triangle ABC in which BC is equal to 5.9 centimeter and angle B 60 degree and angle C 45.

In the previous question, we have given two sides and one angle, in this question, we have given two angles and only one side. So, firstly draw a rough sketch of triangle ABC and mark the given dimensions.

Firstly draw a line segment BC 5.9 centimeter construct 2 CB x 90 degree as we shown in the last example how can we construct angle of 90 degree so now taking CES enter CES enter draw a line of 5 arca of 5 centimeter firstly open the compass 5 centimeter when we mark an arc here it is an arc and join the line join AC obtain the required triangle a b c.

**Construction of Isosceles Triangle**

Now, let's construct an isosceles triangle right high angle triangle but in this is the right angle triangle in which only one angle is 90 degree. The length of two sides is three centimeter and BC is equal to AC.

We have given firstly draw a rough sketch of isalus triangle right ankle ABC in which bc is equal to AC what is the isolus triangle in which two sides of triangle are equal that is called iceless triangle so that means measure of bc and EAC is 3 centimeter and angle ACB is equal to 90 degree.

Step of construction draw a line segment BC 3 centimeter construct angle ABC X now we have to construct angle BCA XY because we have to required the angle measure of C 90 degree that means we take say C as Center firstly make a semicircle now draw two arcs and cut here put the compass on first track and now from the second and join this line it becomes 90 degrees now what happened we have to draw also the arc of three centimeter now taking ASEA Center and opening of three centimeter draw an arc to intersect C X at point AIDS now join a B to obtain the ROC required isalus right angle triangle ABC in with this form we can waves ABC that means it is a right angle triangle.

"WEBVTTKind: captionsLanguage: engood morning student in our first part of construction we had already discussed about how to construct an equivalent equilateral triangle isalus triangle and Scallon triangle with the help of help of compass now in this in the part the second part of construction we discussed about how to construct a an a right triangle and angle of 60 degree angle of 120 degree how can we draw it so moving to our first question that is side angle side cataria that means two sides and one angle are equal this is called side angle side cut area so construction of a triangle when lamps of two of its sides and an included angle are given that means we have given length of two sides and also given one angle so firstly let construct a triangle ABC in which a be five point one centimeter AC 4 point 8 centimeter and angle BAC that means a angle represent 60 degree so now first construction draw a rough sketch of triangle ABC and mark the given dimension step of construction draw a line segment a B of 5 s 0.1 centimeter why we draw a five point one centimeter because we have to draw an an a angle measure of 60 degree also remember which angle we have to draw that means we have to draw the deadline according to the angle so construct angle B ax is equal to b a c b AC is equal to 60 degree now draw an arc of 4 point 8 centimeter taking a as centre with the cuts a a AC ad C a B ad C so now firstly we draw a line a B that means five point one centimeter so how can we draw it I'm telling you firstly draw a line 5.1 centimeter with the help of ruler starting from zero and five point one centimeter so now in the next step in the next step make an arc take es Center draw a semicircle give the line name a be five point one centimeter now again mark and arc put here that means end of the semicircle right from a now join this line with the help of ruler so now we join the line give it to name see and when we measure with the help of this that means it makes a 60 degree angle so now join sorry firstly we have to make an arc of 4 point 8 centimeter because we also given measure of ASC is equal to 4 point 8 centimeter so that means with the help of compass firstly open the compass for point 8 centimeter and make an arc here is an arc so now join B and C that means it is over a triangle of which criteria we follow side angle side because two sides are equal that means 4 point 8 centimeter it is also 4 point 8 centimeter and angle is 60 degree so in this way we can form an angle moving to next question construct triangle it is a sign of triangle de F such that de is equal to 5 centimeter DF is equal to 3 centimeter at M angle e DF is equal to 90 degree so construction firstly draw a rough sketch of triangle de FB EF and mark the given dimension step of construction draw a line segment de of 5 centimeter why we write the why we draw a line de 5 centimeter because we have to consider the angle Dena value of angle D is 90 degree second step angle e DX is equal to 90 degree that means firstly we draw a semicircle then mark the arcs and add wine this line so draw the arcs of radius three for a centimeter de as a center cutting DX at F they also join EF d EF is a required triangle so let's move how can we draw angle of 90 degree firstly draw a line be5 centimeter now draw a semicircle we can arc then we draw the angle of 90 degree please here mark another tox now draw a line so it become a 90 degree angle so next step we have to make an arc of three centimeter here it is a three-centimeter give it a name f now join the X and E so it is a right angle triangle case number third angle side angle criterion construction of triangle when two of its angles and an included side are given let construct a triangle ABC in which BC is equal to five point six centimeter and angle B 60 degree and angle C 45 in the previous question we have given two sides and one angle in this question we have given two angles and only one side so firstly draw a rough sketch of triangle ABC and mark the given dimensions step of construction firstly draw a line of five point six centimeter give it a name B and C because we have to find the measure of angle B 60 degree and angle C is equal to 45 degrees so now next step draw a semicircle taking BS enter make an arc now join the line when we measure it with the help of protector we see that it is a 60-degree angle so also we know that we have to find the value of B that means 60 degree now moving to next step we also find the angle u of angle C 45 degree so firstly we have to draw angle of 90 degree then half of the 90 degree it becomes a 45 so now draw another semicircle taking now C as a centre make an arc from the right and also from the left now make to another arcs please the compass on first arc now please put it on second join the line when we measure measure it with protector it become a 90 degree so how can we find the angle of 45 degree now mark and another arc then we have it and draw a line so it is a angle of 45 degrees in this way we can draw two angles and one side join the line five point six centimeter e Y X now construct BC by 45 degree and by bisecting the right angle R as shown let a a point of intersection of BX + C by B X and C by now ABC's ax required triangle moving to deaths that is our hska Tyria construction of right triangle when its hypotenuse and one side are given let's construct a right triangle ABC in which bc 3.9 centimeter anger be 90 degree and hypotenuse AC is equal to 5 centimeter look at this figure so here bc in 3 / 9 centimeter and a be 90 degree value of AC 5 centimeter so step of construction draw a rough sketch of triangle ABC and mark the given dimensions so now moving to next that means draw a line segment be seen 3.9 centimeter 3 / 9 centimeter construct 2 CB x 90 degree as we shown in the last example how can we construct angle of 90 degree so now taking CES enter CES enter draw an arc with radius 5 centimeter to intersect B X that means taking CES enter draw a line of 5 arca of 5 centimeter firstly open the compass 5 centimeter when we mark an arc here it is an arc and join the line join AC obtain the required triangle a b c similar we construct an isosceles triangle right high angle triangle but is the right angle triangle in which only one angle is 90 degree and a ch3 centimeter we have given firstly draw a rough sketch of isalus triangle right ankle ABC in which bc is equal to AC what is the isolus triangle in which two sides of triangle are equal that is called iceless triangle so that means measure of bc and EAC is 3 centimeter and angle ACB is equal to 90 degree step of construction draw a line segment BC 3 centimeter construct angle ABC X now we have to construct angle BCA XY because we have to required the angle measure of C 90 degree that means we take say C as Center firstly make a semicircle now draw two arcs and cut here put the compass on first track and now from the second and join this line it becomes 90 degrees now what what happened we have to draw also the arc of three centimeter now taking ASEA Center and opening of three centimeter draw an arc to intersect C X at point AIDS now join a B to obtain the ROC required isalus right angle triangle ABC in with this form we can waves ABC that means it is a right angle trianglegood morning student in our first part of construction we had already discussed about how to construct an equivalent equilateral triangle isalus triangle and Scallon triangle with the help of help of compass now in this in the part the second part of construction we discussed about how to construct a an a right triangle and angle of 60 degree angle of 120 degree how can we draw it so moving to our first question that is side angle side cataria that means two sides and one angle are equal this is called side angle side cut area so construction of a triangle when lamps of two of its sides and an included angle are given that means we have given length of two sides and also given one angle so firstly let construct a triangle ABC in which a be five point one centimeter AC 4 point 8 centimeter and angle BAC that means a angle represent 60 degree so now first construction draw a rough sketch of triangle ABC and mark the given dimension step of construction draw a line segment a B of 5 s 0.1 centimeter why we draw a five point one centimeter because we have to draw an an a angle measure of 60 degree also remember which angle we have to draw that means we have to draw the deadline according to the angle so construct angle B ax is equal to b a c b AC is equal to 60 degree now draw an arc of 4 point 8 centimeter taking a as centre with the cuts a a AC ad C a B ad C so now firstly we draw a line a B that means five point one centimeter so how can we draw it I'm telling you firstly draw a line 5.1 centimeter with the help of ruler starting from zero and five point one centimeter so now in the next step in the next step make an arc take es Center draw a semicircle give the line name a be five point one centimeter now again mark and arc put here that means end of the semicircle right from a now join this line with the help of ruler so now we join the line give it to name see and when we measure with the help of this that means it makes a 60 degree angle so now join sorry firstly we have to make an arc of 4 point 8 centimeter because we also given measure of ASC is equal to 4 point 8 centimeter so that means with the help of compass firstly open the compass for point 8 centimeter and make an arc here is an arc so now join B and C that means it is over a triangle of which criteria we follow side angle side because two sides are equal that means 4 point 8 centimeter it is also 4 point 8 centimeter and angle is 60 degree so in this way we can form an angle moving to next question construct triangle it is a sign of triangle de F such that de is equal to 5 centimeter DF is equal to 3 centimeter at M angle e DF is equal to 90 degree so construction firstly draw a rough sketch of triangle de FB EF and mark the given dimension step of construction draw a line segment de of 5 centimeter why we write the why we draw a line de 5 centimeter because we have to consider the angle Dena value of angle D is 90 degree second step angle e DX is equal to 90 degree that means firstly we draw a semicircle then mark the arcs and add wine this line so draw the arcs of radius three for a centimeter de as a center cutting DX at F they also join EF d EF is a required triangle so let's move how can we draw angle of 90 degree firstly draw a line be5 centimeter now draw a semicircle we can arc then we draw the angle of 90 degree please here mark another tox now draw a line so it become a 90 degree angle so next step we have to make an arc of three centimeter here it is a three-centimeter give it a name f now join the X and E so it is a right angle triangle case number third angle side angle criterion construction of triangle when two of its angles and an included side are given let construct a triangle ABC in which BC is equal to five point six centimeter and angle B 60 degree and angle C 45 in the previous question we have given two sides and one angle in this question we have given two angles and only one side so firstly draw a rough sketch of triangle ABC and mark the given dimensions step of construction firstly draw a line of five point six centimeter give it a name B and C because we have to find the measure of angle B 60 degree and angle C is equal to 45 degrees so now next step draw a semicircle taking BS enter make an arc now join the line when we measure it with the help of protector we see that it is a 60-degree angle so also we know that we have to find the value of B that means 60 degree now moving to next step we also find the angle u of angle C 45 degree so firstly we have to draw angle of 90 degree then half of the 90 degree it becomes a 45 so now draw another semicircle taking now C as a centre make an arc from the right and also from the left now make to another arcs please the compass on first arc now please put it on second join the line when we measure measure it with protector it become a 90 degree so how can we find the angle of 45 degree now mark and another arc then we have it and draw a line so it is a angle of 45 degrees in this way we can draw two angles and one side join the line five point six centimeter e Y X now construct BC by 45 degree and by bisecting the right angle R as shown let a a point of intersection of BX + C by B X and C by now ABC's ax required triangle moving to deaths that is our hska Tyria construction of right triangle when its hypotenuse and one side are given let's construct a right triangle ABC in which bc 3.9 centimeter anger be 90 degree and hypotenuse AC is equal to 5 centimeter look at this figure so here bc in 3 / 9 centimeter and a be 90 degree value of AC 5 centimeter so step of construction draw a rough sketch of triangle ABC and mark the given dimensions so now moving to next that means draw a line segment be seen 3.9 centimeter 3 / 9 centimeter construct 2 CB x 90 degree as we shown in the last example how can we construct angle of 90 degree so now taking CES enter CES enter draw an arc with radius 5 centimeter to intersect B X that means taking CES enter draw a line of 5 arca of 5 centimeter firstly open the compass 5 centimeter when we mark an arc here it is an arc and join the line join AC obtain the required triangle a b c similar we construct an isosceles triangle right high angle triangle but is the right angle triangle in which only one angle is 90 degree and a ch3 centimeter we have given firstly draw a rough sketch of isalus triangle right ankle ABC in which bc is equal to AC what is the isolus triangle in which two sides of triangle are equal that is called iceless triangle so that means measure of bc and EAC is 3 centimeter and angle ACB is equal to 90 degree step of construction draw a line segment BC 3 centimeter construct angle ABC X now we have to construct angle BCA XY because we have to required the angle measure of C 90 degree that means we take say C as Center firstly make a semicircle now draw two arcs and cut here put the compass on first track and now from the second and join this line it becomes 90 degrees now what what happened we have to draw also the arc of three centimeter now taking ASEA Center and opening of three centimeter draw an arc to intersect C X at point AIDS now join a B to obtain the ROC required isalus right angle triangle ABC in with this form we can waves ABC that means it is a right angle triangle\n"