**Caution and Regrouping in Addition**

In addition, caution is taken to ensure accurate calculations. This can occur when dealing with large numbers or multiple digits. For example, consider two numbers 5, 3, 2 and 3, 7, 7. In this scenario, the ones place digits are added first, resulting in 2 plus 7 equals 9. The next step involves adding the tens place digits, which results in 3 plus 7 equals 10. Since we have a zero in the tens place, we carry over the one to the hundreds place and write it as 1 on the hundred's place. Finally, we add the hundreds place digits, resulting in 5 plus 3 plus 1 equals 9. Our overall answer is 909.

**Regrouping Hundreds**

Another caution involves regrouping hundreds when adding two-digit numbers. Consider the quotient of two-digit number a = 32 and three-digit number b = 367. Initially, we add the ones place digits, which results in 2 plus 7 equals 9. Then, we add the tens place digits, resulting in 3 plus 6 equals 9 again. Finally, we add the hundreds place digits, which gives us 8 plus 3 equals 11. Since we know that 1100 equals 10^3 + 100, we write one on the hundred's place and one on the thousand's place to get our final answer of 1911.

**Regrouping Hundreds: Further Example**

Another example of regrouping hundreds involves adding two-digit numbers a = 39 and three-digit number b = 346. Initially, we add the ones place digits, resulting in 9 plus 7 equals 16. Then, we add the tens place digits, which results in 3 plus 6 equals 9 again. Finally, we add the hundreds place digits, which gives us 8 plus 4 equals 12. Since we know that 1000 = 10^3 + 100, we write one on the hundred's place and one on the thousand's place to get our final answer of 1201.

**Addition with PI and Regrouping**

Consider adding PI e regrouping both the tens and ones places. Initially, we add the ones place digits, resulting in 5 plus 9 equals 14. Then, we write 4 in the ones place and one on the tens place. Next, we add the tens place digits, which results in 1 plus 9 plus 4 equals 14 again. We then write four in the tens place and one on the hundreds place. In the final step, we add the hundreds place digits, resulting in 6 plus 2 plus 1 equals 9. Our final answer is 94.

**Adding Bigger Numbers**

Now, consider adding larger numbers. We have two numbers 3,4,8,2 and 5,0,0,4. Initially, we add the ones place digits, which results in 2 plus 4 equals 6. Then, we add the tens place digits, resulting in 8 plus 0 equals 8. Next, we add the hundreds place digits, which gives us 4 plus 0 equals 4. Finally, we add the tens place digits of the second number, which results in 3 plus 5 equals 8. Our overall answer is 808.

**Estimating Answers**

To estimate answers, consider two numbers 43,6 and 34,2. We know that 43,6 lies between 400 and 500, while 34,2 lies between 300 and 400. When we add these numbers, we get an answer of 77,8. Therefore, our estimated answer is between 700 and 900.

**Story Sums Based on Addition**

Consider a scenario where there are 350 cows in a cattle shed and two buffaloes. To find the total number of animals, we can use story sums based on addition. We start by adding the number of cows to zero since there are no cows initially. Then, we add the number of buffaloes, which is equal to 2 + 1/2 or simply 2 and a half. Since we cannot have a fraction of an animal, we can approximate this as 3. We then round down to 3 animals in the cattle shed.

**Additional Information**

It's worth noting that addition can be used to solve various real-world problems, such as calculating the total number of animals in a farm or finding the sum of two large numbers. By understanding the different techniques involved in addition, we can become proficient in solving these types of problems with ease.

"WEBVTTKind: captionsLanguage: engood morning students I hope you all are well today I am here to teach you mathematics we are doing our second chapter of mathematics that is addition in this chapter we are doing three things three digit addition with regrouping adding bigger number and story sums based on addition we start our chapter with three digit addition with regrouping our first number is 4 3 7 and the second number is 3 5 6 when we add both these numbers see clearly 4 3 7 + 3 5 6 we are doing our quotient step by step in the first step you can clearly see 7 & 6 are on the ones place first we add ones and regrouped when we add 7 plus 6 is equal to 13 we know 13 equals to 1 x + 3 ones so we write 1 so we write 3 in the ones place and 1 in the tens place and in the second step we add tens three plus five plus one equals two 9/10 and we write nine in the tens place in the third step we add hundreds four plus three equals to 7 so we write seven on the hundreds place now we are doing one example of this type of caution we have two numbers 6 3 5 & 2 4 9 you can see 5 & 9 is on ones place first we add both these numbers 5 plus 9 equals to 14 you know 14 ones equal to 1/10 plus 4 for once so we write for on ones place and one on tans place and in the next step we add tens one plus three plus four equals to 8 so we write eight on tans position and in the next step we add hundreds six plus two equals to 8 so we write eight on the hundreds position now we are doing next type of caution in this type of question we regrouped tens place we have two numbers five seven one and three three one students remember ten tens equal to 110 tens equal to 100 now we start our question see first of all we add ones number one plus one equals two to and in the next step we add tens number seven plus three equals 210 we know ten tens equals to 100 plus zero tens so I write zero on the tens place and one on the hundreds place and in the next step either I add five plus three plus one equals two nine and our final answer is nine zero two and our final answer is nine zero two now we are doing one more example of this type of caution we have two numbers 5 3 2 & 3 7 7 first of all we add ones place digits 2 plus 7 equals to 9 in the next step we add tens digits three plus seven equals to 10 110 I write zero on the tens place and one on the hundreds place because we know 1 10 equals to 100 plus 0 tens and in the next step we add hundreds digits 5 plus 3 plus 1 equals to 9 and our overall and final answer is nine zero nine now we start our next type of caution regrouping hundreds students see clearly we have two numbers nine hundred and three hundred in the first step we at once zero plus zero equals to zero and in the next step we add tens that is zero plus zero equals to zero again and in the third step we add hundreds in the next step we add hundreds that is nine plus three equals to 12 so I write you know 12 100 equals to 10 100 plus 200 and students you know 10 100 equals to 1000 so I write 2 on the 100 place and one on the thousand place and our overall answer is one two zero zero okay now we are doing one more example of regrouping hundreds in this quotient we have two digit number three digit numbers a three two and three is six seven first of all we add two numbers ones place that our own ones place two plus seven equals to 9 and in the next step we add tens place that is three plus six equals to nine again and in the next step we add hundreds place disease data eight plus three equals to eleven I write one because we know 1100 equals to 10 100 plus 110 100 equals to 1000 plus 100 so I write one on that 100 place and another one on the thousand place and our overall answer is 1 1 9 9 1 1 9 9 now we are doing next question add PI e regrouping the tens and ones in this question both the regrouping are occurs ones and tens so first of all we add once we have digits that is 5 and 9 5 plus 9 equals to 14 so I write 4 in the ones place and one on the tens place in the next step I add 1 plus 9 plus 4 equals to 14 again and awry and I write four in the tens place and 1 in the hundreds place and in the next step I add hundreds place digits 6 plus 2 plus 1 equals to 9 and our final answer is 9 4 for now we are doing addition of bigger numbers we have two numbers 3 4 8 2 and 5 0 0 4 right in this way now we start addition in the first step we add 2 plus 4 equals to 6 in the next step we add 8 plus 0 equals to 8 and in the third step we add 4 plus 0 equals to 4 and in the last step we add 3 plus 5 equals to 8 I hope you got it now we are doing estimating the answer in this question let two numbers 4 5 6 & 3 4 0 we have 2 numbers 3 4 5 6 & 3 4 0 we know 4 5 6 lies between the 400 and 500 and 340 lies between the 300 and 400 so when we estimate we estimate that our answer lies between the 700 and 900 ok now we are doing one question of this type of we have two numbers 3 5 8 & 4 2 6 3 5 8 lies between the 300 and 400 4 to 6 lies between the 400 and 500 our estimate and Sewer lies between the 700 and 900 but when we actually add both these numbers we got 7 8 4 as arms were so this is the question of estimating now we do story sums based on addition we take one example in the cattle-shed there are 350 cows and two one two buffaloes how many animals are there in the cattle shed in the solution we write number of cows is equal to 350 number of buffaloes is equal to 2 1 2 now we add both these numbers 0 plus 2 equals to 0-5 plus 1 equals to 6 3 plus 2 equals to Phi so there are five six two animals in the cattle shed I hope you all understand the topic very well thank you for watching this videogood morning students I hope you all are well today I am here to teach you mathematics we are doing our second chapter of mathematics that is addition in this chapter we are doing three things three digit addition with regrouping adding bigger number and story sums based on addition we start our chapter with three digit addition with regrouping our first number is 4 3 7 and the second number is 3 5 6 when we add both these numbers see clearly 4 3 7 + 3 5 6 we are doing our quotient step by step in the first step you can clearly see 7 & 6 are on the ones place first we add ones and regrouped when we add 7 plus 6 is equal to 13 we know 13 equals to 1 x + 3 ones so we write 1 so we write 3 in the ones place and 1 in the tens place and in the second step we add tens three plus five plus one equals two 9/10 and we write nine in the tens place in the third step we add hundreds four plus three equals to 7 so we write seven on the hundreds place now we are doing one example of this type of caution we have two numbers 6 3 5 & 2 4 9 you can see 5 & 9 is on ones place first we add both these numbers 5 plus 9 equals to 14 you know 14 ones equal to 1/10 plus 4 for once so we write for on ones place and one on tans place and in the next step we add tens one plus three plus four equals to 8 so we write eight on tans position and in the next step we add hundreds six plus two equals to 8 so we write eight on the hundreds position now we are doing next type of caution in this type of question we regrouped tens place we have two numbers five seven one and three three one students remember ten tens equal to 110 tens equal to 100 now we start our question see first of all we add ones number one plus one equals two to and in the next step we add tens number seven plus three equals 210 we know ten tens equals to 100 plus zero tens so I write zero on the tens place and one on the hundreds place and in the next step either I add five plus three plus one equals two nine and our final answer is nine zero two and our final answer is nine zero two now we are doing one more example of this type of caution we have two numbers 5 3 2 & 3 7 7 first of all we add ones place digits 2 plus 7 equals to 9 in the next step we add tens digits three plus seven equals to 10 110 I write zero on the tens place and one on the hundreds place because we know 1 10 equals to 100 plus 0 tens and in the next step we add hundreds digits 5 plus 3 plus 1 equals to 9 and our overall and final answer is nine zero nine now we start our next type of caution regrouping hundreds students see clearly we have two numbers nine hundred and three hundred in the first step we at once zero plus zero equals to zero and in the next step we add tens that is zero plus zero equals to zero again and in the third step we add hundreds in the next step we add hundreds that is nine plus three equals to 12 so I write you know 12 100 equals to 10 100 plus 200 and students you know 10 100 equals to 1000 so I write 2 on the 100 place and one on the thousand place and our overall answer is one two zero zero okay now we are doing one more example of regrouping hundreds in this quotient we have two digit number three digit numbers a three two and three is six seven first of all we add two numbers ones place that our own ones place two plus seven equals to 9 and in the next step we add tens place that is three plus six equals to nine again and in the next step we add hundreds place disease data eight plus three equals to eleven I write one because we know 1100 equals to 10 100 plus 110 100 equals to 1000 plus 100 so I write one on that 100 place and another one on the thousand place and our overall answer is 1 1 9 9 1 1 9 9 now we are doing next question add PI e regrouping the tens and ones in this question both the regrouping are occurs ones and tens so first of all we add once we have digits that is 5 and 9 5 plus 9 equals to 14 so I write 4 in the ones place and one on the tens place in the next step I add 1 plus 9 plus 4 equals to 14 again and awry and I write four in the tens place and 1 in the hundreds place and in the next step I add hundreds place digits 6 plus 2 plus 1 equals to 9 and our final answer is 9 4 for now we are doing addition of bigger numbers we have two numbers 3 4 8 2 and 5 0 0 4 right in this way now we start addition in the first step we add 2 plus 4 equals to 6 in the next step we add 8 plus 0 equals to 8 and in the third step we add 4 plus 0 equals to 4 and in the last step we add 3 plus 5 equals to 8 I hope you got it now we are doing estimating the answer in this question let two numbers 4 5 6 & 3 4 0 we have 2 numbers 3 4 5 6 & 3 4 0 we know 4 5 6 lies between the 400 and 500 and 340 lies between the 300 and 400 so when we estimate we estimate that our answer lies between the 700 and 900 ok now we are doing one question of this type of we have two numbers 3 5 8 & 4 2 6 3 5 8 lies between the 300 and 400 4 to 6 lies between the 400 and 500 our estimate and Sewer lies between the 700 and 900 but when we actually add both these numbers we got 7 8 4 as arms were so this is the question of estimating now we do story sums based on addition we take one example in the cattle-shed there are 350 cows and two one two buffaloes how many animals are there in the cattle shed in the solution we write number of cows is equal to 350 number of buffaloes is equal to 2 1 2 now we add both these numbers 0 plus 2 equals to 0-5 plus 1 equals to 6 3 plus 2 equals to Phi so there are five six two animals in the cattle shed I hope you all understand the topic very well thank you for watching this video\n"